Angle between the vectors i-j- and j-k- is-

The correct option is A 60 ^∘ cos θ = (î +ĵ ).(ĵ +k̂ ) √( 1+1 ) .√( 1+1 ) #160; = 0+0+1+0 √( 2 ) .√( 2 ) #160; = 12 #160;which gives: θ ...

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Angle between...

Question

Angle between the vectors $(\to i + \to j)$ and $(\to j + \to k)$ is:

60^{\circ}

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90^{\circ}

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180^{\circ}

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0^{\circ}

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