- CAB-60- the value of - CBD is

In the figure, ACB is an equilateral triangle. So, nbsp;∠ CBA=60^∘. Now, nbsp;∠ CBD=∠ ABD ∠ CBA ∠ CBD=180^∘ 60^∘ ∠ CBD=120^∘ Therefore, the value of the ...

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Standard IX

Mathematics

Construction of 60 degree Angle and Its Proof

∠ CAB=60∘, th...

Question

$∠ C A B = 60^{\circ}$ , the value of $∠ C B D$ is
120

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Solution

The correct option is A 120
In the figure, $△ A C B$ is an equilateral triangle. So, $∠ C B A = 60^{\circ}$ .

Now, $∠ C B D = ∠ A B D - ∠ C B A ∠ C B D = 180^{\circ} - 60^{\circ} ∠ C B D = 120^{\circ}$

Therefore, the value of the $∠ C B D$ is $120^{\circ} .$

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In the figure below, $△$ ABC $≅$ $△$ BED, $∠$ DEB = $115^{\circ}$ and $∠$ CAB = $25^{\circ}$ . It can be concluded that

Q. In a quadrilateral ABCD,which is not a trapezium,it is know that

∠ D A B = ∠ A B C = 60

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. Then:

In the given figure, AB and CD are two intersecting chords of a circle. If $∠ C A B = 40^{\circ} a n d ∠ B C D = 80^{\circ} then ∠ C B D = ?$

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∠CAB=60∘, the value of ∠CBD is120

The correct option is A 120In the figure, △ACB is an equilateral triangle. So, ∠CBA=60∘. Now, ∠CBD=∠ABD−∠CBA∠CBD=180∘−60∘∠CBD=120∘ Therefore, the value of the ∠CBD is 120∘.

$∠ C A B = 60^{\circ}$ , the value of $∠ C B D$ is
120

The correct option is A 120
In the figure, $△ A C B$ is an equilateral triangle. So, $∠ C B A = 60^{\circ}$ .

Now, $∠ C B D = ∠ A B D - ∠ C B A ∠ C B D = 180^{\circ} - 60^{\circ} ∠ C B D = 120^{\circ}$

Therefore, the value of the $∠ C B D$ is $120^{\circ} .$