$∠ D < ∠ B$
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

In $△ A B D$
$A B > A D$ (AB is the longest side of quadrilateral ABCD)
$∠ B D A > ∠ D B A$ (Angle opposite to the greater side is
greater) ... (1)
In $△ B D C$
$B C > C D$ (CD is the smallest side of quadrilateral ABCD)
$=> ∠ B D C > ∠ C B D$ (Angle opposite to the
greater side is greater) ... (2)
On adding equations (1) and (2), we obtain
$∠ B D C + ∠ B D A > ∠ D B A + ∠ C B D$
$=> ∠ D > ∠ B$

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