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Question

Angle inscribed in a minor segment is

A
acute
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B
obtuse
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C
right
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D
straight
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Solution

The correct option is C obtuse

Let AB be any chord and O be the center of a circle

WKT angle subtended by an arc at the cener is twice the angle subtended by any part of the alternate segment of the circle.

AOB=2ACB

AOB<180

2<180

ACB<90

Angle in major segment is acute

Now BA is major arc and angle AOB is angle formed by it in the alternate segment.

2AOB=m(arcBA)=360m(arcAB)

2ADB=360AOB

2ADB>360280

ADB>90

Angle in minor segment is obtuse


857159_274108_ans_b96a92577cf94f0387318275f5a95a70.png

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