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Question

Angle made by the line xcos30o+ysin30o+5=0, with the positive Xaxis, is :

A
π/6
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B
2π/3
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C
5π/6
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D
π/3
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Solution

The correct option is C 2π/3

Given that.

xCos300+ySin300+5=0

ySin300=xCos3005

y=xCos300Sin3005Sin300

y=x Cot3005Cosec300


On Comparing that.

y=mx+c

m=Cot300

m=Cot(1800300) Cot(1800A)=CotA

m=Cot 1500m=tan(27001200)


We know that

m = tanθ=tan1200

θ=1200

θ=120×π180

θ=2π3


Hence, this is the answer


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