Angle of a prism is $30^{\circ}$ and its refractive index is $\sqrt{2}$ and one of the surface is silvered. At what angle of incidence, a ray should be incident on one surface so that after reflection from the silvered surface, it retraces its path

30^{\circ}

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60^{\circ}

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45^{\circ}

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s i n^{- 1} \sqrt{1.5}

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Solution

The correct option is C $45^{\circ}$
This is the case when light ray is falling normally an second surface.
Hence by using $μ = \frac{s i n i}{s i n A} \Rightarrow \sqrt{2} = \frac{s i n i}{s i n 30^{\circ}} \Rightarrow s i n i = \sqrt{2} \times \frac{1}{2} \Rightarrow i = 45^{\circ}$

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Angle of a prism is 30∘ and its refractive index is √2and one of the surface is silvered. At what angle of incidence, a ray should be incident on one surface so that after reflection from the silvered surface, it retraces its path

The correct option is C 45∘This is the case when light ray is falling normally an second surface. Hence by using μ=sinisinA⇒√2=sinisin30∘⇒sini=√2×12⇒i=45∘

Angle of a prism is $30^{\circ}$ and its refractive index is $\sqrt{2}$ and one of the surface is silvered. At what angle of incidence, a ray should be incident on one surface so that after reflection from the silvered surface, it retraces its path

The correct option is C $45^{\circ}$
This is the case when light ray is falling normally an second surface.
Hence by using $μ = \frac{s i n i}{s i n A} \Rightarrow \sqrt{2} = \frac{s i n i}{s i n 30^{\circ}} \Rightarrow s i n i = \sqrt{2} \times \frac{1}{2} \Rightarrow i = 45^{\circ}$