Question

Angle of dip at a place is ${60}^0$ and earth's magnetic field is $8\mu T$. Its horizontal component $B_H$ is :

• A. $4\sqrt{3\mu }T$
• B. $4\mu T$
• C. $\frac{8}{\sqrt{3}}\mu T$
• D. $8\sqrt{3\mu }T$

Answer 1

Answer: (B)

$4\mu T$

Horizontal component of magnetic field is given by,
$B_H=B_E\cos \theta$

$=8\times \cos {60}^{\circ }$
$=8\times \frac{1}{2}=4\mu T$