Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9o44′
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
44′
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−5o16′
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A24o44′ Angle strain in cyclopropane is 24o44′ Deviation d=109o28′−α2 α is the bond angle in cyclopropane. Deviation d=109o28′−60o2=+24o44′