Angles in a right-angled triangle are 30- 60- 90- - Find the ratio of the corresponding sides-

Let assume one length is 6 cm AB/AC =sin 30 AC =12 cm tan 60 = x/6 √(3)=x/6 6√(3)=x Ratio is 12 : 6√(3):6 2:√(3):1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Continuity of a Function

Angles in a r...

Question

Angles in a right-angled triangle are 30º,60º ,90 º. Find the ratio of the corresponding sides?

Open in App

Solution

Let assume one length is 6 cm
AB/AC =sin 30
AC =12 cm
tan 60 = $\frac{x}{6}$
$\sqrt{3} = \frac{x}{6} 6 \sqrt{3} = x$
Ratio is $12 : 6 \sqrt{3} : 6$
$2 : \sqrt{3} : 1$

Suggest Corrections

Similar questions

Q. If the angles of a triangle are

30^{\circ}, 60^{\circ}, 90^{\circ}

, then what is the ratio of corresponding sides?

Q. Find the ratio of the sides of a triangle whose interior angles are

30^{o}, 60^{o} a n d 90^{o}

degrees?

$The corresponding sides of two triangles △ A B C and △ P Q R are in the ratio 4:23.$ $If ∠ B = 60^{\circ} and ∠ A = 40^{\circ}, find the measure of ∠ R .$

In a

△ A B C, ∠ A = 60^{\circ}, ∠ B = 30^{\circ} a n d ∠ C = 90^{\circ} .

Then find the ratio of the sides AC: BC: AB.

Q. If the angles of a triangle are

30^{o}, 60^{o}

and

90^{o}

, then what is the ratio of the sides opposite to these angles?

Join BYJU'S Learning Program

Angles in a right-angled triangle are 30º,60º ,90 º. Find the ratio of the corresponding sides?

Let assume one length is 6 cm AB/AC =sin 30 AC =12 cm tan 60 = x6 √3=x66√3=x Ratio is 12:6√3:6 2:√3:1

Let assume one length is 6 cm
AB/AC =sin 30
AC =12 cm
tan 60 = $\frac{x}{6}$
$\sqrt{3} = \frac{x}{6} 6 \sqrt{3} = x$
Ratio is $12 : 6 \sqrt{3} : 6$
$2 : \sqrt{3} : 1$