Given,
The angles of a quadrilateral are (4x)∘ , 5(x+2)∘ , (7x−20)∘ and 6(x+3)∘.
We know that the sum of all the interior angles in a quadrilateral is 360∘
Hence,
(4x)∘+5(x+2)∘+(7x−20)∘+6(x+3)∘=360∘4x+5x+10∘+7x−20∘+6x+18∘=360∘22x+8∘=360∘22x=360∘−8∘22x=352∘x=(35222)∘we get.x=16∘