Angles of a triangle are x -10- x -40- and 2 x -30- - What is the value of x -A- 30-B- 40-C- 20-D- 10-

The correct option is B 40^∘Given that the angles of the triangle are (x + 10^∘), (x + 40^∘) and 2x 30^∘. Sum of the angles of a triangle = 180^∘ Angle sum p ...

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Byju's Answer

Standard VII

Mathematics

Angle Sum Property of a Triangle

Angles of a t...

Question

Angles of a triangle are $(x + 10^{\circ}) (x + 40^{\circ})$ and $(2 x - 30^{\circ}$ . What is the value of x?

30^{\circ}

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40^{\circ}

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20^{\circ}

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10^{\circ}

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Solution

The correct option is B $40^{\circ}$
Given that the angles of the triangle are $(x + 10^{\circ})$ , $(x + 40^{\circ})$ and $2 x - 30^{\circ}$ .
Sum of the angles of a triangle $= 180^{\circ}$ {Angle sum property}
$\Rightarrow (x + 10)^{\circ} + (x + 40)^{\circ} + (2 x - 30)^{\circ} = 180^{\circ}$
$\Rightarrow 4 x + 50 - 30 = 180^{\circ}$
$\Rightarrow 4 x = 160^{\circ}$
$\Rightarrow x = 40^{\circ}$

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Angles of a triangle are (x+10∘)(x+40∘) and (2x−30∘. What is the value of x?

The correct option is B 40∘Given that the angles of the triangle are (x+10∘), (x+40∘) and 2x−30∘. Sum of the angles of a triangle =180∘ {Angle sum property} ⇒(x+10)∘+(x+40)∘+(2x−30)∘=180∘ ⇒4x+50−30=180∘ ⇒4x=160∘ ⇒x=40∘

Angles of a triangle are $(x + 10^{\circ}) (x + 40^{\circ})$ and $(2 x - 30^{\circ}$ . What is the value of x?