Question

Angles of a triangle are $(x+{10}^{\circ }),(x+{40}^{\circ })$, and $(2x-{30}^{\circ })$. The value of x is ___ degrees.

Answer 1

Given that the angles of the triangle are $(x+{10}^{\circ })$, $(x+{40}^{\circ })$, and $(2x-{30}^{\circ })$.
Sum of the angles of a triangle $={180}^{\circ }$ [Angle sum property]
$\Rightarrow (x+10{)}^{\circ }+(x+40{)}^{\circ }+(2x-30{)}^{\circ }={180}^{\circ }$
$\Rightarrow 4x+50-30={180}^{\circ }$
$\Rightarrow 4x={160}^{\circ }$
$\Rightarrow x={40}^{\circ }$