Angles of a triangle are x - 10- x - 40- and 2x - 30- Find the value of x-

Given that the angles of the triangle are (x + 10^∘), (x + 40^∘) and 2x 30^∘. By Angle sum property, Sum of the angles of a triangle = 180^∘ nbsp; ⇒ (x + 1 ...

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Byju's Answer

Standard VII

Mathematics

Angle Sum Property of a Triangle

Angles of a t...

Question

Angles of a triangle are $(x + 10^{\circ}), (x + 40^{\circ})$ and $(2 x - 30^{\circ})$ . Find the value of x.

$30^{\circ}$

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$40^{\circ}$

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$20^{\circ}$

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$10^{\circ}$

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Solution

The correct option is B
$40^{\circ}$

Given that the angles of the triangle are $(x + 10^{\circ})$ , $(x + 40^{\circ})$ and $2 x - 30^{\circ}$ .

By Angle sum property,
Sum of the angles of a triangle $= 180^{\circ}$
$\Rightarrow (x + 10)^{\circ} + (x + 40)^{\circ} + (2 x - 30)^{\circ} = 180^{\circ}$
$\Rightarrow 4 x + 50 - 30 = 180^{\circ}$
$\Rightarrow 4 x = 160^{\circ}$
$\Rightarrow x = 40^{\circ}$

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Angles of a triangle are (x+10∘),(x+40∘) and (2x−30∘). Find the value of x.

The correct option is B 40∘ Given that the angles of the triangle are (x+10∘), (x+40∘) and 2x−30∘. By Angle sum property, Sum of the angles of a triangle =180∘ ⇒(x+10)∘+(x+40)∘+(2x−30)∘=180∘ ⇒4x+50−30=180∘ ⇒4x=160∘ ⇒x=40∘

Angles of a triangle are $(x + 10^{\circ}), (x + 40^{\circ})$ and $(2 x - 30^{\circ})$ . Find the value of x.