Angles opposite to the equal sides of a triangle are equal.If true enter 1 else 0.
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Solution
Consider △ABC, ∠B=∠C Construction: Draw a median AD on BC, which meets AB at D. Hence, BD=DC Now, In △ABD and △ACD ∠B=∠C AD=AD (Common) BD=DC Thus, △ABD≅△ACD (SAS rule) Thus, ∠B=∠C (By CPCT)