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Question

Angular displacement of any particle as given θ=ω0t+12αt2 where ω0 & α are constant if ω0=1 rad/sec,α=1.5 rad/sec2 then in t=2 sec, angular velocity will be (in rad/sec)

A
1
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B
5
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C
3
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D
4
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Solution

The correct option is D 4

Given that,

α=1.5rad/sec2

ω0=1rad/sec

t=2sec

Now, the angular displacement is

θ=ω0t+12αt2.....(I)

Now, the angular velocity is

dθdt=ω0+22αt

dθdt=1+1.5×2

dθdt=4rad/sec

Hence, the angular velocity is 4 rad/sec


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