Angular momentum for $p -$ shell electron is:

\frac{3 h}{π}

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zero

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\frac{\sqrt{2} h}{2 π}

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none of these

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Solution

The correct option is A $\frac{\sqrt{2} h}{2 π}$
Orbital angular momentum for p-shell electron is $\frac{(\sqrt{l (l + 1)}) h}{2 π}$
For $p -$ shell $l = 1$
So, Angular momentum = $\frac{(\sqrt{1 (1 + 1)}) h}{2 π} = \frac{\sqrt{2} h}{2 π}$

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