The correct option is D moment of inertia and angular velocity
The angular momentum of a moving particle about a point is defined as ;
→L=→r×→p
As, →p=m→v ∴→L=m(→r×→v)
In case of circular motion of a particle
→L=mvrsin90∘^n
where ^n is the unit vector perpendicular to the plane of motion in accordance with right hand screw rule.
→L=m(rω)r^n (∴v=rω)
=mr2ω^n
→L=I→ω [as mr2=I and ω^n=→ω]
Hence, the correct answer is option (d).