Angular momentum of a particle about the origin is L = 6t + 8, then net torque about the origin is

8 N-m

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6 N-m

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2 N-m

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0 N-m

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Solution

The correct option is B 6 N-m
$τ = \frac{d}{d t} (L)$
Where, $L = 6 t + 8$
$τ = \frac{d}{d t} (6 t + 8) = 6$ N-m

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