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Shapes of Orbitals and Nodes

Angular momen...

Question

Angular momentum of an electron in Bohr's orbit of hydrogen atom is 4.22 * 10^-34kg m²s^-1. Calculate the wavelength of the spectral line when the electron Falls from this level to the next lower level.

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Solution

calculate n by the formula,

mvr=nh/2pi

and rearrange

n = mvr(2pi)/h = 4.2210^-34(2pi)/h=4
V(wave number)=RZ2(1/n1^2-1/n2^2)
R=Rydberg constant =1.097107
n1=3 n2=4 z= 1
Substituteing this values we get
V=51. 35
So wave length =1/v=1/51. 35=0.09147m

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