Angular speed of particle undergoing circular motion of radius 2 m varies with times as - -2t -1 rad-s- Distance travelled by particle in 0 to 1 s is

Answer (2) ω=2t+1 dθdt=2t+1 ⇒θ=∫_0^1(2t+1)dt ⇒θ = 2 radian Distance = θ r = 4 m ...

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Standard XII

Physics

Correlation to Linear Motion

Angular speed...

Question

Angular speed of particle undergoing circular motion of radius $2 m$ varies with time(s) as $ω = (2 t + 1)$ rad/s. Distance travelled by particle in $0$ to $1 s$ is

3 m

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1 m

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4 m

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2 m

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Solution

The correct option is C $4 m$
Answer (2)
$ω = 2 t + 1$
$\frac{d θ}{d t} = 2 t + 1$
$\Rightarrow θ = 1 \int 0 (2 t + 1) d t$
$\Rightarrow θ = 2 radian$
Distance $= θ r$
$= 4 m$

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Angular speed of particle undergoing circular motion of radius 2 m varies with time(s) as ω=(2t+1) rad/s. Distance travelled by particle in 0 to 1 s is

The correct option is C 4 mAnswer (2) ω=2t+1 dθdt=2t+1 ⇒θ=1∫0(2t+1)dt ⇒θ=2 radian Distance =θr =4 m

Angular speed of particle undergoing circular motion of radius $2 m$ varies with time(s) as $ω = (2 t + 1)$ rad/s. Distance travelled by particle in $0$ to $1 s$ is

The correct option is C $4 m$
Answer (2)
$ω = 2 t + 1$
$\frac{d θ}{d t} = 2 t + 1$
$\Rightarrow θ = 1 \int 0 (2 t + 1) d t$
$\Rightarrow θ = 2 radian$
Distance $= θ r$
$= 4 m$