Angular velocity of hour hand of a watch is:

\frac{π}{43200} r a d / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{30} r a d / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{21600} r a d / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{π}{1800} r a d / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{π}{21600} r a d / s$
Time rate of change of angular displacement is angular velocity.
Angular velocity $= \frac{a n g l e t r a c e d}{t i m e t a k e n}$
Time period of hour hand is $12 h$ .
So, $ω = \frac{2 π}{12} r a d / s$
$= \frac{2 π}{12 \times 60 \times 60} r a d / s$
$= \frac{π}{21600} r a d / s$

Suggest Corrections

Similar questions

Q. The length of a second hand in a watch is

1 cm

. The magnitude of change in velocity of its tip in

15

seconds is

Q. A clock is in x- y plane. Find angular velocity of second hand of a clock (in rad/s).

The length of second's hand in a watch is 1 cm. The change in velocity of its tip in 15 seconds is

Q. Let

S \subset (0, π)

denotes the set of values of

x

satisfying the equation

8^{1 + | cos x | + {cos}^{2} x + | {cos}^{3} x | + \dots + \infty} = 4^{3}

. Then,

S =

Let $S \subset (0, π)$ denote the set of values of x satisfying the equation $8^{1 + | c o s x | + c o s^{2} x + | c o s^{3} x | + . . . t o \infty} = 4^{3}$ .Then, S=

Join BYJU'S Learning Program

Angular velocity of hour hand of a watch is:

The correct option is C π21600rad/sTime rate of change of angular displacement is angular velocity. Angular velocity =angletracedtimetakenTime period of hour hand is 12h.So, ω=2π12rad/s =2π12×60×60rad/s =π21600rad/s