Anhydride of nitrous acid is:

N_{2} O

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N O

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N_{2} O_{3}

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N_{2} O_{4}

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Solution

The correct option is C $N_{2} O_{3}$
Oxidation number of $H N O_{2}$ is $+ 3$ .

The anhydride of $H N O_{2}$ has also $+ 3$ for nitrogen atoms.

Oxidation number of $N$ in $N_{2} O \to + 1$

Oxidation number of $N$ in $N O \to + 2$

Oxidation number of $N$ in $N_{2} O_{3} \to + 3$

Oxidation number of $N$ in $N_{2} O_{4} \to + 4$

Thus, anhydride of $H N O_{2}$ is $N_{2} O_{3}$ .

Hence, option $C$ is correct.

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