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Question

# Anhydrous AlCl3 is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution. Given : Ionization energy for AlCl3=5137 kJ mol −1, ΔHydration for Al3+=−4665 kJ mol−1, ΔHydration for Cl−=−381 kJ mol−1.

A
340 kJ/mol
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B
290 kJ/mol
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C
91 kJ/mol
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D
671 kJ/mol
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Solution

## The correct option is C −671 kJ/molThe enthalpy change ΔH for the reaction AlCl3+(aq)⟶AlCl3(aq) is :ΔH= Energy released during hydration - Energy used during ionization =[(−4665)−(3×381)]+5137= −5808+5137=−671 kJ/molSince the Energy released during hydration is greater than the Energy used during ionization, AlCl3 will become ionic in aqueous solution.

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