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Heat of Formation

Anhydrous A...

Question

Anhydrous $A l C l_{3}$ is a covalent compound. From the data given below, predict whether it would remain covalent or become ionic in an aqueous solution .

Ionisation energy of $A l = 5137 k J m o l^{- 1}$ , $Δ H$ hydration for $A l^{3 +} = - 4665 k J m o l^{- 1};$ $Δ H$ hydration for $C l^{-} = - 381 k J m o l^{- 1}$

A

Ionic

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B

Covalent

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C

Partially ionic

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D

Partially covalent

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Solution

The correct option is A Ionic
Total hydration energy is $- 4665 + 3 \times (- 381) = - 5808 k J m o l^{- 1}$ and ionization energy is $5137 k J m o l^{- 1}$ . So some energy will use in breaking bond. So, $A l C l_{3}$ become ionic in aqueous solution.

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Similar questions

A l C l_{3}

is covalent from the data given below predict whether it would remain covalent or become ionic in aqueous solution.

Ionization energy for A l C l_{3} = 5137 k J m o l^{- 1}

Δ H_{hydration}

A l^{+ 3} i s - 4665 k J m o l^{- 1}

Δ H_{hydration}

C l^{-}

k J m o l^{- 1}

A l {C l}_{3}

is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution.

Given : Ionization energy for

A l {C l}_{3} = 5137

^{- 1}

Δ_{H y d r a t i o n}

{A l}^{3 +} = - 4665

^{- 1}

Δ_{H y d r a t i o n}

{C l}^{-} = - 381

^{- 1}

A l C l_{3}

is covalent from the data given below predict whether it would remain covalent or ionic in aqueous solution.

Ionization energy for A l C l_{3} = 5137 k J m o l^{- 1}

Δ H_{hydration}

A l^{+ 3} = - 4665 k J m o l^{- 1}

Δ H_{hydration}

C l^{-}

k J m o l^{- 1}

Q. Ionisation energy of

A l t o A l^{3 +} = 5137 k J m o l^{- 1} △ H_{h y d r a t i o n} o f : A l^{3 +} = - 4665 k J m o l^{- 1} a n d f o r C l^{-} = - 381 k J m o l^{- 1} .

Which of the following statement is correct?

A l C l_{3}

is covalent. from the data given below
Lattice Energy

= 5137 K J m o l^{- 1}

△ H h y d r a t i o n A l^{3 +} = - 4665 K J / m o l^{- 1}

△ H h y d r a t i o n C l^{-} = - 381 K J / m o l^{- 1}

Identify the correct statement-

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