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Question

Anisole is treated with HI. Products obtained are:-

A
Ethyl alcohol and phenyl iodide
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B
methyl alcohol and benzene
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C
methyl iodide & phenyl iodide
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D
methyl iodide & phenol
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Solution

The correct option is D methyl iodide & phenol

In case of anisole, methylphenyl oxonium ion, is formed by protonation of ether. The bond between OCH3 is weaker than the bond between OC6H5 because the carbon of phenyl group is sp2 hybridised and there is a partial double bond character. Therefore the attack by I– ion breaks OCH3 bond to form CH3I. Phenols do not react further to give halides because the sp2 hybridised carbon of phenol cannot undergo nucleophilic substitution reaction needed for conversion to the halide.


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