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Question

Anisole is treated with HI under two different conditions.
C+DHI(g)C6H5OCH3conc.HI−−−−A+B The nature of A to D will be


A

A and B are CH3 I and C6H5OH, while C and D are CH3OH and C6H5I

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B

A and B are CH3OH and C6H5I, while C and D are CH3I and C6H5OH

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C

Both A and B as well as both C and D are CH3I and C6H5OH

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D

A and B are CH3I and C6H5OH, while there is no reaction in the second case

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Solution

The correct option is C

Both A and B as well as both C and D are CH3I and C6H5OH


Although in both cases products are CH3I and C6H5OH ;the two reaction follow different mechanism.
C6H5OCH3Hl(g)−−SN2CH3I+C6H5OHC6H5OCH3conc.Hl−−−SN1CH3I+C6H5OH
Remember that during SN1 reaction, CH+3 is formed because it is more stable than C6H+5.


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