Question

Anita saves $Rs4.65$ daily, find the least number of days she will save the exact number of rupees.

Answer 1

Solution: Since, $Rs4.65=465paise$

and the exact number of rupees will be $100$ paise

So, we have to find the L.C.M. of $465$, $100$.

Prime factors of $100=2\times 2\times 5\times 5$

Prime factors of $465=3\times 5\times 31$

L.C.M. of $465$ and $100$ is $2\times 2\times 3\times 5\times 5\times 31=9300$

So, the boy saves $9300$ paise.

Hence, least number of days required to save $9300$ paise $=\frac{9300}{465}$

​$=20$ days.