Anjali swam for $50 s e c o n d s$ at a speed of $4.5 m / s$ . Then, she swam for another $70 s e c o n d s$ at a speed of $1.5 m / s$ . Find the distance covered by anjali in metres.

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Solution

As we know,
$D i s \tan c e = s p e e d \times t i m e$
Distance covered by Anjali in first $50 s e c o n d s = 4.5 \times 50 = 225 m e t r e s$
distance covered by Anjali in next $70 s e c o n d s = 1.5 \times 70 = 105 m e t r e s$
So , The total distance covered by Anjali = $225 + 105 = 330 m e t r e s$

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Anjali swam for 50seconds at a speed of 4.5m/s. Then, she swam for another70secondsat a speed of 1.5m/s. Find the distance covered by anjali in metres.

As we know,Distance=speed×timeDistance covered by Anjali in first 50seconds=4.5×50=225metresdistance covered by Anjali in next 70seconds=1.5×70=105metresSo , The total distance covered by Anjali = 225+105=330metres

Anjali swam for $50 s e c o n d s$ at a speed of $4.5 m / s$ . Then, she swam for another $70 s e c o n d s$ at a speed of $1.5 m / s$ . Find the distance covered by anjali in metres.