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Question

Answer each of the following questions in one word or one sentence or as per exact requirement of for question:

In any triangle ABC, find the value of a sin(BC)+b sin (CA)+c sin (AB.)

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Solution

a sin(BC)+b sin (CA)+c sin (AB.)=k sin A sin (BC)+k sin B sin (CA)+k sin C sin (AB)=k sin (π(B+C)) sin (BC)+k sin (π(C+A)) sin (CA)+k sin (π(A+B)) sin (AB)=k sin (B+C) sin (BC)+k sin (C+A) sin (CA) + k sin (A+B) sin (AB)=k[sin2 Bsin2 C+sin2 Csin2 A+sin2 Asin2 B]=k×0=0


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