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Question

Answer each of the following questions in one word or one sentence or as per exact requirement of for question:

In a ΔABC, if sin A and sin B are the roots of the equation c2x2c(a+b)x+ab=0, then find C.

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Solution

c2x2c(a+b)x+ab=0sin A and sin B are the roots of the equation,sin A+sin B=c(a+b)c2=(a+b)csin A sin B=abc2sin Asin B=(sin A+sin B)24 sin A.sin B=(a+bc)24abc2=a2+b2+2ab4abc2=a2+b22abc2=(ab)2c2=left(ab)csinA+sinB=(a+b)c ...(i)sinAsinB=(ab)c ...(ii)Adding (i) and (ii), we get,sinA=ac and sinB=bcsinA=PerpendicularhypotenuseSo, In ΔABC,one of the side = a, another side = b,Third side = c a2+b2=c2C=90


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