Answer for

3(3z-5)-5(2z-1)=4(2z-3)-17

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Solution

3 (3z-5) - 5 (2z-1) = 4 (2z-3) - 17

17 = 4 (2z-3) - 3 (3z-5) + 5 (2z-1)

17 = 8z - 12 + 10z - 5 - 9z + 15

17 = 8z + 10z - 9z - 12 - 5 + 15

17 = 18z - 9z + 10 - 12

17 = 9z - 2

19 = 9z

z = 19/9

z=2.11

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1 + 3 + 5 + 7 + 9

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Without adding find the sum

(i) 1 + 3 + 5 + 7 + 9

(ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19

(iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

\frac{5}{a - 3} + \frac{7}{2 a - 6}

\frac{17}{2 a - 6}

1

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