Question

Answer the following based on the sequence of the number given below:

3 2 1 1 5 6 4 2 8 9 3 9 1 1 4 8 2 4 2 9 3 3 9 4 2 4

In the above given sequence how many times a number is the square root of the previous number?

• A. $6$
• B. $7$
• C. $8$
• D. $9$

Answer 1

The correct option is B $7$

According to the question, we need to find the pair of numbers in which the second number is square root of the first number.

This type of pairs are

Starting from left

(1	1), (4 2), (9 3), (1 1), (4 2), (9 3), (4 2)

So, there are total 7 such pairs.

Hence, option B is correct.