Answer the following question from the given figure.
Here the solid is composed of cube, cylinder and cone.
Here,
The curved surface area of cone is P.
The curved surface area of cylinder is Q.
The area of the base of cone and cylinder is R and the Total surface area of cube is S.
Then, find the total surface area of solid.

P + Q - R + S

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P + Q - 2R + S

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P + Q + R + S

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P + Q + 2R + S

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Solution

The correct option is D P + Q - R + S
T.S.A. of the solid
= C.S.A. of cone + C.S.A. of cylinder + T.S.A. of cube - Area of base of the cylinder
= P + Q + S - R
= P + Q - R + S
Hence, option A is correct.

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The correct option is D P + Q - R + ST.S.A. of the solid= C.S.A. of cone + C.S.A. of cylinder + T.S.A. of cube - Area of base of the cylinder= P + Q + S - R= P + Q - R + SHence, option A is correct.

The correct option is D P + Q - R + S
T.S.A. of the solid
= C.S.A. of cone + C.S.A. of cylinder + T.S.A. of cube - Area of base of the cylinder
= P + Q + S - R
= P + Q - R + S
Hence, option A is correct.