Question

Answer the following questions:
A point charge $q$ moving with speed $v$ enters a uniform magnetic field $B$ that is acting into the plane of the paper as shown. What is the path followed by the charge $q$ and in which plane does it move?

Answer 1

The force experienced by the charge is given by

$\overrightarrow{F}=q(\overrightarrow{V}\times \overrightarrow{B})$

When $\overrightarrow{V}$ is perpendicular to $\overrightarrow{B}$ the force on the charge particle acts as the centripetal force and makes

It move along a circular. Path followed by charge is anticlockwise in $X-Y$ plane.

The point charge moves in the plane perpendicular both

$\overrightarrow{V}$ and $\overrightarrow{B}$.