Anti-Markovnikov's rule is only applicable for addition of :

H C l

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H B r

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H I

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All of these

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Solution

The correct option is C $H B r$
Peroxide or kharash effect : In the presence of peroxide and light, addition of HBrto unsymmetrical alkenes occur contrary to Markovnikov's rule.

But HCl and HI do not show peroxide effect.

With HBr, both the propagation steps are exothermic and HBr adds to the double bond by free- radical mechanism.

$C H_{3} - C H = C H_{2} + H - B r \to C H_{3} - C H (B r) - C H_{3}$

Hence the correct option is B.

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