Antilog of the number $(- 8.654)$ is equal to

2.18 \times 10^{- 8}

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2.18 \times 10^{- 9}

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2.218 \times 10^{- 9}

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2.218 \times 10^{- 8}

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Solution

The correct option is D $2.218 \times 10^{- 9}$
$(- 8.654) = - 8 + (- 0.654)$
$= - 8 + (- 0.654) + 1 - 1$
$= - 9 + (1 - 0.654) = - 9 + 0.346$

Actual digits of 0.346 from the log table $= 2.218$

$∴$ $a n t i log (- 8.654) = 2.218 \times 10^{- 9}$

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Antilog of the number (−8.654) is equal to

The correct option is D 2.218×10−9(−8.654)=−8+(−0.654)=−8+(−0.654)+1−1=−9+(1−0.654)=−9+0.346Actual digits of 0.346 from the log table =2.218∴ antilog(−8.654)=2.218×10−9

Antilog of the number $(- 8.654)$ is equal to

The correct option is D $2.218 \times 10^{- 9}$
$(- 8.654) = - 8 + (- 0.654)$
$= - 8 + (- 0.654) + 1 - 1$
$= - 9 + (1 - 0.654) = - 9 + 0.346$

Actual digits of 0.346 from the log table $= 2.218$

$∴$ $a n t i log (- 8.654) = 2.218 \times 10^{- 9}$