Question

Antiport transport occurs in the axoplasm of neuron, when neuron is under resting stage. As action potential generates at axon there is a change in pump proteins of axolemma which is about $-70\text{mV}$ and will reach to $-60\text{mV}$. This will cause opening of $N{a}^{+}$ VGC because it is permeable for uptake of $N{a}^{+}$ ion however it cannot easily diffuse $K^{+}$ ion.

Mark the correct statement according to the given paragraph.

• A. Action potential will stop passive transport of $N{a}^{+}/K^{+}$ pump
• B. Change in resting potential occurs due to influx of $K^{+}$
• C. Action potential will stop active transport of $N{a}^{+}/K^{+}$ pump
• D. Change in resting potential occurs due to efflux of $N{a}^{+}$

Answer 1

The correct option is C Action potential will stop active transport of $N{a}^{+}/K^{+}$ pump

As the action potential is generated at axon hillock, it will stop $N{a}^{+}/K^{+}$ pump. The sodium–potassium pump mechanism moves 3 sodium ions out and 2 potassium ions in, thus, in total, removing one positive charge carrier from the intracellular space by using ATP (i.e., active transport).

Change in resting potential occurs due to influx of $N{a}^{+}$.