Anu is four years older than Sunil. Eight years ago, Anu was three times Sunil's age. Find the ages of Sunil and Anu.

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Solution

Anu is four year older than sunil
If sunil's age = x
anu's age = x+4

Anu was 3 times sunil's age 8 yeas ago
(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10

Sunil's age = 10years
Anu's age = 10+4 = 14years

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Anu is four years older than Sunil. Eight years ago, Anu was three times Sunil's age. Find the ages of Sunil and Anu.

Anu is four year older than sunil If sunil's age = x anu's age = x+4 Anu was 3 times sunil's age 8 yeas ago (x+4) - 8 = 3(x-8) ⇒ x - 4 = 3x - 24 ⇒ x - 3x = -24 + 4 ⇒ -2x = -20 ⇒ x = -20/-2 = 10 Sunil's age = 10years Anu's age = 10+4 = 14years

Anu is four year older than sunil
If sunil's age = x
anu's age = x+4

Anu was 3 times sunil's age 8 yeas ago
(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10

Sunil's age = 10years
Anu's age = 10+4 = 14years