Question

Any number of the form $6^n,nϵN$ always ends with the digit

• A. 4
• B. 0
• C. 8
• D. 6

Answer 1

The correct option is D 6

$6^n=(2\times 3{)}^n=2^n\times 3^n$

$\Rightarrow 2$ and 3 are the only prime factors of $6^n$$.$

From the Fundamental Theorem of Arithmetic and prime factorisation, the digit at the units place must be a factor of both 2 and 3.

Hence, the correct answer is option (d).