Any tangent to the circle x2+y2=a2 meets the axes of co-ordinates in A and B respectively. The rectangle OACB is completed. The locus of the vertex of the rectangle OACB is the curve x−2+y−2=a−2.
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Solution
Let tangent AB be xα+yβ=1. p=r gives 1α2+1β2=1a2 ∴ Locus of vertex C(α,β) is x−2+y−2=a−2.