Question

Any teacher can be included in the committee?

• A. 626
• B. 718
• C. 924
• D. 844
• E. None of these

Answer 1

The correct option is C 924

When any teacher can be included in the committee, then number of ways
${=}^{12}{C}_6$ (by short trick 1)
$=\frac{12!}{(12-6)!\times 6!}=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}=11\times 2\times 3\times 2\times 7$
= 924