AOB is straight line- The value of - AOP is nbsp- 70-110-120-60-

The correct option is B 110^∘ Since AOB is straight line, ∠ AOP + ∠ BOP =180^∘ (Linear pair) ie, x+20^∘+x 20^∘=180^∘ ⇒ 2x=180^∘ ⇒ x =90^∘ ∴∠ AOP =x+20^∘=90+20= ...

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Standard VII

Mathematics

Linear Pair Axiom

AOB is straig...

Question

AOB is straight line. The value of $∠ A O P$ is ___.

$70^{\circ}$

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$110^{\circ}$

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$60^{\circ}$

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$120^{\circ}$

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Solution

The correct option is B
$110^{\circ}$

Since AOB is straight line,

$∠ A O P + ∠ B O P = 180^{\circ}$ (Linear pair)

ie, $x + 20^{\circ} + x - 20^{\circ} = 180^{\circ}$

$\Rightarrow 2 x = 180^{\circ}$

$\Rightarrow x = 90^{\circ}$

$∴ ∠ A O P = x + 20^{\circ} = 90 + 20 = 110^{\circ}$

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AOB is straight line. The value of ∠AOP is ___.

The correct option is B 110∘ Since AOB is straight line, ∠AOP+∠BOP=180∘ (Linear pair) ie, x+20∘+x−20∘=180∘ ⇒2x=180∘ ⇒x=90∘ ∴∠AOP=x+20∘=90+20=110∘

AOB is straight line. The value of $∠ A O P$ is ___.

The correct option is B
$110^{\circ}$

Since AOB is straight line,

$∠ A O P + ∠ B O P = 180^{\circ}$ (Linear pair)

ie, $x + 20^{\circ} + x - 20^{\circ} = 180^{\circ}$

$\Rightarrow 2 x = 180^{\circ}$

$\Rightarrow x = 90^{\circ}$

$∴ ∠ A O P = x + 20^{\circ} = 90 + 20 = 110^{\circ}$