90∘+∠AOB+90∘+∠APB=360∘
∠AOB+∠APB=180∘
Therefore ∠AOB and ∠APB are always supplementary.
So, option B is the answer.
Two tangents PA and PB are drawn to a circle with center O from an external point P. Prove that ∠APB=2∠OAB [3 MARKS]
Two tangents PA and PB are drawn from an external point P to the circle with centre O, such that ∠APB =120∘what is the relation between OP and AP?
In fig., there are two concentric circles with center O and of radii 5 cm and 3 cm. From an external point P, tangents PA and PB are drawn to these circles. If AP = 12 cm, find the length of BP [3 MARKS]