AP whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20 is 3, 7, 11, 15, ....... If true then enter 1 and if false then enter 0
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Solution
Let a and d be the first term and common difference of AP respectively. Now, a5=a+4d=19 ...(1) a13−a8=(a+12d)−(a+7d)=20 ⇒5d=20 ⇒d=4 On substituting the value of d in (1), we get a+4×4=19 ⇒a=3 Therefore the AP is a,a+d,a+2d,a+3d... 3,7,11,15...