Question

Application of laws of exponents based on fractional and algebraic powers
Solve for $x$:
$2^{2x+1}=8$

Answer 1

Given that:

$2^{2x+1}=8$

$\because 8=2^3$

Since we know that if base is same in both left and right side of equality than powers are equal.

So,

$2^{2x+1}=2^3$

$2x+1=3$

$2x=2$

$x=1$

Answer.