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Byju's Answer
Standard VIII
Mathematics
Powers with Negative Exponents
Application o...
Question
Application of laws of exponents based on numerical powers
simplify:
(i)
2
3
2
2
1
5
(ii)
(
1
3
3
)
7
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Solution
(i)
2
3
2
⋅
2
1
5
We know that,
(
a
m
a
n
=
a
m
+
n
)
⇒
2
3
2
+
1
5
=
2
17
10
(ii)
(
1
3
3
)
7
⇒
1
(
3
3
)
7
=
1
3
21
(
(
a
m
)
n
=
a
m
n
)
.
∴
2
3
2
⋅
2
1
5
=
2
17
10
and
(
1
3
3
)
7
=
1
3
21
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