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Approximate ...

Question

Approximate $K_{c}$ for the reaction at $25^{o} C$ will be:
$Z n (s) + {C u}^{2 +} (a q) = {Z n}^{3 +} (a q) + C u (s)$
$E_{{Z n}^{2 +} / Z n}^{o} = - 0.76 V E_{C u / {C u}^{2 +}}^{o} = - 0.34 V$

10^{11}

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10^{33}

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10^{18}

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10^{14}

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Solution

The correct option is D $10^{18}$
The equation should be-
$Z n (s) + {C u}^{2 +} (a q) ⇌ {Z n}^{2 +} (a q) + C u (s)$
Given,
$E_{{Z n}^{2 +} / Z n}^{0} = - 0.76$ (For oxidation it will be +0.76)
$E_{C u / {C u}^{2 +}}^{0} = - 0.34$ (For reduction it will be +0.34)
So, Total ${E_{C e l l}^{0} = E}_{{Z n}^{2 +} / Z n}^{0} + E_{C u / {C u}^{2 +}}$
= 0.76+0.34
=1.1
Therefore, $E_{C e l l}^{0} = \frac{0.0592 V}{n} l o g K 1.1 = \frac{0.0592}{1} l o g K l o g K = \frac{1.1}{0.0592} l o g K = 18.58 K = 10^{18}$

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