Approximate normal composition of alveolar air is?

14 % O_{2}, 6 % C O_{2}, 80 % N_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16 % O_{2}, 3 % C O_{2}, 81 % N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

21 % O_{2}, 2 % C O_{2}, 77 % N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 % O_{2}, 8 % C O_{2}, 82 % N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $14 % O_{2}, 6 % C O_{2}, 80 % N_{2}$
Alveolar air represents the air located in the respiratory part of the lungs which takes part in gas exchange with the blood in the pulmonary capillaries. The air is mixed with nitrogen approximately 70-80%, oxygen around 13-14%, 5-6% carbon dioxide, and water vapour around 5-6%.
So, the correct option is A.

Suggest Corrections

Similar questions

lim n \to \infty (\frac{1}{1 - n^{2}} + \frac{2}{1 - n^{2}} + . . . . . . + \frac{n}{1 - n^{2}})

N_{2}

O_{2}

N_{2}

N_{2}

N_{2}

80

N_{2}

20

O_{2}

293 K

76 c m H g

The correct order of bond strength is $N_{2}^{+}, N_{2}$ and $N_{2}^{-}$

density of dry air containing only N2 and O2 is 1.15 g/l at 740mm of hg and 300 k what is the % composition of N2 by mass in the air

Join BYJU'S Learning Program