Question

Approximate the numbers to the nearest (a) integer and (b) tenth :

$\sqrt{8}$.

Answer 1

Given number: $\sqrt{8}$.

We know that

$\sqrt{4}=2$ and $\sqrt{9}=3$

So, $\sqrt{8}$ will lie in between $2$ and $3$.

Now, $\sqrt{8}=2.82842...$

(a) Approximate the numbers $\sqrt{8}$ to the nearest integer.

Let $\sqrt{8}=2.82$

The value of $\sqrt{8}$ lies between $2$ and $3$ but is more closer to the integer $3$.

Approximate value of $\sqrt{8}$ to the nearest integer is $3$.

(b) Approximate value of $\sqrt{8}$ to the nearest tenth:

Round the number to the nearest tenth by removing the digits after one digit of decimal point.

Approximate value of $\sqrt{8}$ to the nearest tenth is $2.8$.

Hence, approximate value of $\sqrt{8}$ to the nearest integer is $3$and approximate value of $\sqrt{8}$ to the nearest tenth is $2.8$.