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Question

Approximate value of 16(0.98)4

A
4.54
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B
17.28
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C
17.4
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D
8.1
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Solution

The correct option is B 17.28
The approximate value of (1+x)n for x<1 is 1+nx
For 16(10.02)4 as 0.02<1
Hence, the approximate value is
16(1+4×0.02) = 16×(1.08) = 17.28

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